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2n^2-7n=24
We move all terms to the left:
2n^2-7n-(24)=0
a = 2; b = -7; c = -24;
Δ = b2-4ac
Δ = -72-4·2·(-24)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{241}}{2*2}=\frac{7-\sqrt{241}}{4} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{241}}{2*2}=\frac{7+\sqrt{241}}{4} $
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